5x^2+3x+20=400

Solution for 5x^2+3x+20=400 equation:

5x^2+3x+20=400

We move all terms to the left:

5x^2+3x+20-(400)=0

We add all the numbers together, and all the variables

5x^2+3x-380=0

a = 5; b = 3; c = -380;
Δ = b2-4ac
Δ = 32-4·5·(-380)
Δ = 7609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{7609}}{2*5}=\frac{-3-\sqrt{7609}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{7609}}{2*5}=\frac{-3+\sqrt{7609}}{10}
$